A physiscs student performed an experiment by taking a beaker with 1 l of water oat 30^(@)C and dropping an iron sphere with temperature 90^(@)C in it .After sometime student tmeasure their equailibrium temperature as 48^(@)C .If the density of iron sphere is 7870 kg m^(-3) then find the volume of the iron sphere specifice heat of iron is 0.110 jcal g^(-1@)C^(-1)

A physiscs student performed an experiment by taking a beaker with 1 l

1.	A physiscs student performed an experiment by taking a beaker with 1 l of water oat 30^(@)C and dropping an iron sphere with temperature 90^(@)C in it .After sometime student tmeasure their equailibrium temperature as 48^(@)C .If the density of iron sphere is 7870 kg m^(-3) then find the volume of the iron sphere specifice heat of iron is 0.110 jcal g^(-1@)C^(-1)
Answer» Solution :Mass of l of water =1 KG `(Deltat)_(W)=48-30=180^(C )` `(Deltat)_(iron) =90 -48=42^(@)C` HEAT absorbed by water =Heat LOST (removed ) from iron `((msDeltat_(w)))/((sDeltat_(iron)))((1000xx1xx18)/(0.110xx42))=3.896 kg` density = `(mass)/(V)` `V=(m)/(d)=(3.896)/(7870)=4.95xx10^(-4m^(3)`