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A piece of ice of mass of `100g` and at temperature `0^(@)C` is put in `200g` of water of `25^(@)C` .How much ice will melt as the temperature of the water reaches `0^(@)C`? The specific heat capacity of water`= 2400 J kg ^(-1)K^(-1)` and the specific latent heat of ice `= 3.4 xx 10^(3)J kg^(-1)` |
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Answer» Heat released by 0.15 kg of water in being cooled to `0^@C=0.15xx1xx20=3kcal` Heat absorbed by ice from `-10^@`C to `0^@C=0.1xx0.5xx10=0.5kcal` The balance heat is available for malting ice. Let m kg of ice melt. Then `mxx80=2.5` or `m=0.03kg` Thus the final temperature is `0^@C` with `0.07kg` of ice and `0.18kg` of water |
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