1.

A piece of steel has a volume of 10 cm^(3) and a mass of 80 g. What is its density in: kg//m^(3)

Answer»

Solution :To convert `1g//cm^(3)` to `kg//m^(3)` we have to multiply by 1000 HENCE `8g//cm^(3)= 8 XX 1000= 8000 kg//m^(3)`


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