A piece of wire is bent in the shape of a a rectangle whose length and width are 35 cm and 20 CM respectively .It is opened and Rebent to form a circular ring. What is the diameter of the Ring?

A piece of wire is bent in the shape of a a rectangle whose length and

1.	A piece of wire is bent in the shape of a a rectangle whose length and width are 35 cm and 20 CM respectively .It is opened and Rebent to form a circular ring. What is the diameter of the Ring?
Answer» 35Step-by-step explanation:The DIAMETER of ring is 35 cm.Step-by-step explanation:We are given the following in the question:Length of rectangle = 35 cmWidth of rectangle = 20 cmPerimeter of rectangle =\begin{gathered}P = 2(l + w)\\P = 2(35 + 20) = 110\end{gathered} P=2(l+w)P=2(35+20)=110 where l is he length and w is the width.Now,Perimeter of rectangle = CIRCUMFERENCE of ringCircumference of circle = \pi dπdwhere d is the diameter of ringEquating values, we get,\begin{gathered}\pi d = 110\\\\\dfrac{22}{7}\times d =110\\\\d = \dfrac{110\times 7}{22} = 35\end{gathered} πd=110722 y ×d=110d= 22110×7 =35 The diameter of ring is 35 cm