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InterviewSolution
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A piece of wood from an archelogical source shows a `.^(14)C` activity which is `60%` of the activity found in fresh wood today. Caculate the age of the archeologival sample. (`t_(1//2)` for `.^(14)C = 5570` year) |
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Answer» `t = (2.303)/(lambda) log (N_(0))/(N)` (`r_(0) prop N_(0)` and `r prop N`) `= (2.303xx5770)/(0.693)` log `(100)/(60)` `= 4253 yr, [:. (r_(0))/(r) = (N_(0))/(N) = (100)/(60)]` |
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