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The intergrated rate equation is `Rt = log, C_(0) - log C_(t)`. The straight line graph is obtained by plotting:A. `t` vs log `C_(t)`B. `(1)/(t)` vs log `C_(t)`C. `t` vs `C_(t)`D. `(1)/(t)` vs log `(1)/(C_(t))` |
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Answer» Correct Answer - `(a)` `log C_(1) vst (log C_(t) = log C_(0) - Rt)` having a `y = c + mx` slope equal to `-R` |
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