1.

The intergrated rate equation is `Rt = log, C_(0) - log C_(t)`. The straight line graph is obtained by plotting:A. `t` vs log `C_(t)`B. `(1)/(t)` vs log `C_(t)`C. `t` vs `C_(t)`D. `(1)/(t)` vs log `(1)/(C_(t))`

Answer» Correct Answer - `(a)`
`log C_(1) vst (log C_(t) = log C_(0) - Rt)` having a
`y = c + mx`
slope equal to `-R`


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