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The half life of `.^(215)At` is `100mu s`. The time taken for the radioacticity of `.^(215)At` to decay to `1//16^(th)` of its initial value is:A. `400mu s`B. `6.3mu s`C. `40mu s`D. `300mu s` |
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Answer» Correct Answer - `(a)` `(1)/(16) = (1)/(2^(4)), :. n = 4, t_(1//2) = 100 mu s` `:. T = t_(1//2) xx n` `= 100xx4 = 400 mu s` |
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