1.

A piece of wood was found to have C^(14)//C^(12) ratio 0.7 times that in a living plant. The time period when the plant died is (Half-life of C^(14) = 5760 yr)

Answer»

2770 YR
2966 yr
2980 yr
3070 yr

Solution :GIVEN, `N_(0) = 1N, N_(t) = 0.70 and t_(1//2) = 57600 yr`
`k = (0.693)/(t_(1//2)) = (0.693)(5760)`
We also know, `k = (2.303)(t) "LOG" (N_(0))/(N_(t)) = (0.693)/(5760)`
or `t = (2.303 xx 5760 xx 0.155)/(0.693) = 2966yr`


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