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a piece of work can be done by 2 men and 5 boys in 5 days. 1/3rd of the work can be done by 3 men and 4 boys in 3 days. how long will it be required by 9 men to do the same work. |
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Answer» Answer: Let the AMOUNT of work done by a MAN alone in a day be M and by a Boy alone be B GIVEN, 2 men and 5 boys together can finish a piece of work in 4 days Amount of work they can do in ONE day 2M+5B = 4 1
-- (1) Similarly, 3M+6B= 3 1
--- (2) Solving equations (1) and (2), we GET B= 36 1
Substituting B in equation (2), we get M= 18 1
Hence, one man alone will take 18 days to do the work and one boy will take 36 days. |
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