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A pipe of circular cross-section of inner radius r and outer radius 2r is bent into a semi circle as shown in the diagram. A fluid of density rho=10^(3)kg//m^(3) is flowing through it. The breaking stress of the material of the pipe is 3xx10^(7)n//m^(2). The maximum velocity with which the fluid can flow in the pipe is kxx100 m//s. find value of k. |
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Answer» SOLUTION :`2rhoAv^(2)=2F` `sigma=(F)/(3pir^(2))=(rhoA)/(3pi)` `sigma=(rhov^(2))/(3)` `v=30m//s` 
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