InterviewSolution
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InterviewSolution
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A pipe of length `l_(1)`, closed at one end is kept in a chamber of gas of density `rho_(1)`. A second pipe open at both ends is placed in a second chamber of gas of density `rho_(2)`. The compressibility of both the gases is equal. Calculate the length of the second pipe if frquency of first overtone in both the cases is equalA. (a) `(4)/(3)l_(1)sqrt((rho_(2))/(rho_(1))`B. (b) `(4)/(3)l_(1)sqrt((rho_(1))/(rho_(2))`C. ( c ) `l_(1)sqrt((rho_(2))/(rho_(1))`D. (d) `l_(1)sqrt((rho_(1))/(rho_(2))` |
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Answer» Correct Answer - B (b) Frequency of first overtone in closed pipe, `v = (3v)/(4l_(1))sqrt((P)/(rho_(1))` ….(i) Frequency of first overtone in open pipe, `v = (1)/(4l_(2))sqrt((P)/(rho_(2))` …(ii) From equation (i) and (ii) rArr `l_(2) = (4)/(3)l_(1)sqrt((rho_(1))/(rho_(2))` |
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