1.

A pipe open at both ends produces a note of frequency f_(1). When the pipe is kept with (3)/(4)th of its length in water, it produces a note of frequency f_(2) The ratio (f_(1))/(f_(2)) is :

Answer»

`(3)/(4)`
`(4)/(3)`
`(1)/(2)`
2

Solution :`n_(0)= f_(1) = (V)/(2l ) `
`f_(2) = (v)/(4xx(1)/(4) l ) = (v)/(l) `
` therefore(f_(1))/(f_(2))= ( (V)/(2l))/((V)/(l)) = (1)/(2) ` .
correct choice is (c).


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