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A piston filled with `0.04` mole of an ideal gas expands reversible from `50.0mL` at a constant temperature of `37.0^(@)C` . As it does so, it absorbs `208J` of heat. The value of `q` and `W` for the process will be `(R=8.314J//molK` , `1n7.5=2.01)`A. `q=+208 J`, `w=+208 J`B. `q=208 J`, `w=-208 J`C. `q=-208 J`, `w=-208 J`D. `q=-208 J`, `w=+208 J` |
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Answer» Correct Answer - B For isothermal expansion of an ideal gas, `DeltaV=0` Hence, from first law of thermodynamics, `DeltaU=q+w`, we have `q=-w`. A process involves adsoption of heat, i.e., it is endothermic `:. Q=-208 J`. Hence `w=-208 J` |
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