A Plain Carbon Steel Contains 45 Wt% Of Proeutectoid Ferrite. What Is

1.	A Plain Carbon Steel Contains 45 Wt% Of Proeutectoid Ferrite. What Is Its Average Carbon Content In Weight Percent? I Know That You Need To Use A Tie Line In The Phase Diagram, But My Book Does Not Really Give A Good Example To Go By?
Answer» The calculation is so easy if you have the ironcarbon diagram in your mind. Proeutectoid FERRITE is ferrite formed before EUTECTOID transformation. At 0.8 wt% carbon, we got 100% austenite before the transformation and at 0.02wt% carbon, we got 100% ferrite, and between these two values of carbon content, we have different amounts of proeutectoid ferrite. Considering that, we have x wt% carbon we CALCULATE proeutectoid ferrite using the tie line. Proeutectoid ferrite amount = (0.8x)/ (0.80.02)* 100=45 ==> x=0.45 wt% You can check it with eyes. At the MIDDLE of the tie line, we MUST have 50% austenite, 50% ferrite; and it is at (0.80.02)/ 2=0.38%C. We have 45% ferrite, which is less than 50% so we are closer to eutectoid point (0.8%C); so the carbon content must be more than 0.38%. The calculation is so easy if you have the ironcarbon diagram in your mind. Proeutectoid ferrite is ferrite formed before eutectoid transformation. At 0.8 wt% carbon, we got 100% austenite before the transformation and at 0.02wt% carbon, we got 100% ferrite, and between these two values of carbon content, we have different amounts of proeutectoid ferrite. Considering that, we have x wt% carbon we calculate proeutectoid ferrite using the tie line. Proeutectoid ferrite amount = (0.8x)/ (0.80.02)* 100=45 ==> x=0.45 wt% You can check it with eyes. At the middle of the tie line, we must have 50% austenite, 50% ferrite; and it is at (0.80.02)/ 2=0.38%C. We have 45% ferrite, which is less than 50% so we are closer to eutectoid point (0.8%C); so the carbon content must be more than 0.38%.

A Plain Carbon Steel Contains 45 Wt% Of Proeutectoid Ferrite. What Is Its Average Carbon Content In Weight Percent? I Know That You Need To Use A Tie Line In The Phase Diagram, But My Book Does Not Really Give A Good Example To Go By?

Answer»

The calculation is so easy if you have the ironcarbon diagram in your mind. Proeutectoid FERRITE is ferrite formed before EUTECTOID transformation. At 0.8 wt% carbon, we got 100% austenite before the transformation and at 0.02wt% carbon, we got 100% ferrite, and between these two values of carbon content, we have different amounts of proeutectoid ferrite. Considering that, we have x wt% carbon we CALCULATE proeutectoid ferrite using the tie line.

Proeutectoid ferrite amount = (0.8x)/ (0.80.02)* 100=45

==> x=0.45 wt%

You can check it with eyes. At the MIDDLE of the tie line, we MUST have 50% austenite, 50% ferrite; and it is at (0.80.02)/ 2=0.38%C.

We have 45% ferrite, which is less than 50% so we are closer to eutectoid point (0.8%C); so the carbon content must be more than 0.38%.

The calculation is so easy if you have the ironcarbon diagram in your mind. Proeutectoid ferrite is ferrite formed before eutectoid transformation. At 0.8 wt% carbon, we got 100% austenite before the transformation and at 0.02wt% carbon, we got 100% ferrite, and between these two values of carbon content, we have different amounts of proeutectoid ferrite. Considering that, we have x wt% carbon we calculate proeutectoid ferrite using the tie line.

Proeutectoid ferrite amount = (0.8x)/ (0.80.02)* 100=45

==> x=0.45 wt%

You can check it with eyes. At the middle of the tie line, we must have 50% austenite, 50% ferrite; and it is at (0.80.02)/ 2=0.38%C.

We have 45% ferrite, which is less than 50% so we are closer to eutectoid point (0.8%C); so the carbon content must be more than 0.38%.

A Plain Carbon Steel Contains 45 Wt% Of Proeutectoid Ferrite. What Is Its Average Carbon Content In Weight Percent? I Know That You Need To Use A Tie Line In The Phase Diagram, But My Book Does Not Really Give A Good Example To Go By?

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