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A planar loop of wire rotates in a uniform magnetic field. Initially at t =0, the plane of the loop is perpendicular to the magnetic field. If it rotates with a period of 10 s about an axis in its plane, then the magnitude of induced emf will be maximum and minimum, respectively at |
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Answer» 2.5 s, 5 s  `RARR OMEGA=(2PI)/T =(2pi)/10` `therefore omega=pi/5`….(1) when `omegat=pi/2`, then flux ASSOCIATED with ring is MINIMUM and induced emf is maximum. `therefore t=(pi//2)/omega = (pi//2)/(pi//s)=5/2`=2.5 s (From equ. (1)) and when `omegat=pi` then flux associated with ring is maximum and induced emf is minimum . `therefore t=pi/omega` `=pi/(pi//5)` (`because` From equation (1)) t=5s `therefore` (2.5 s, 5s) |
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