Saved Bookmarks
| 1. |
A plane electromagnetic wave E=E_(m) cos ( omega t-kx) propagating in vacuum induces the emf E_("ind"), in a square frame with side l. The orientation of the frame is shown in figure. Find the amplitude value epsilon_("ind") , if E_(m)=0.50m V//m, the frquency v=5.0 MHz and l=50 cm. |
|
Answer» SOLUTION :`xi_(i nd)=oint vec(E). dvec(l)=E_(m)l ( cos OMEGAT - cos ( omegat -kl))` `=-2E_(m) l sin ( (omegal)/( 2 c )) sin (omegat-(omegal)/( 2 c ))` Putting the values `E_(m)=50m V//m, l =(1)/(2) metre` `(omegal)/(c)=(2pi vl)/( c) =(pixx10^(8))/( 3 xx 10^(8))=(pi)/( 3)` `xi_(i nd)=50 m V(-sin ((pi)/( 6)))sin ( omegat-((pi)/(6)))` `=-25 sin (omegat+(pi)/(6)-(pi)/(2))=25 cos (omegat-(pi)/( 3))mV` |
|