1.

A plane electromagnetic wave3 of wavelength lambda has an indentsity I. It is propagating along the position Y - direction. The allowed expressions for the electric and magnetic fields are given by

Answer»

`vecE=sqrt((I)/(epsilon_(0)C))cos[(2pi)/(lambda)(y-ct)]hati,vecB=(1)/(c)Ehatk`
`vecE=sqrt((I)/(epsilon_(0)C))cos[(2pi)/(lambda)(y-ct)]hatk,vecB=-(1)/(c)Ehati`
`vecE=sqrt((2I)/(epsilon_(0)C))cos[(2pi)/(lambda)(y-ct)]hatk,vecB=+(1)/(c)Ehati`
`vecE=sqrt((2I)/(epsilon_(0)C))cos[(2pi)/(lambda)(y-ct)]hatk,vecB=-(1)/(c)Ehatj`

Solution :If `E_(0)` is magnitude of ELECTRIC field then `(1)/(2)epsilon_(0)E^(2)xxC=1 rArr E_(0) =sqrt((2I)/(C epsilon_(0)))`
`E_(0)=(E_(0))/(C )`
Direction of `vecExx vecB` will be ALONG `+HATJ`


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