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A plane EM wave travelling in vacuum along z - direction is given by vec(E )=E_(0)sin (kz - omega t)hat(i)andvec(B)=B_(0)sin(kz - omega t)hat(j).Evaluate int vec(E ). Vec(d)l over the rectangular loop 134 shown in figure. |
Answer» Solution :Consider FIGURE given below,![]() ELECTROMAGNETIC waves are propagating in z - direction.Let electric field vector `vec(E )` and `vec(B)` is in x - direction and magnetic field vector is in y - direction. `therefore vec(E ) =E_(0)hat(i)`and`vec(B)=B_(0)hat(j)` As shown in figure line INTEGRATION over square path 1234, `oint vec(E ). vec(d)l = int_(1)^(2)vec(E ).vec(d)l+ int_(2)^(3)vec(E ).vec(d)l+int_(3)^(4)vec(E ).vec(d)l` `= int_(1)^(2) Ed l COS 90^(@)+int_(2)^(3)Edl cos 0^(@)+int_(3)^(4)Edl cos 90^(@)+int_(4)^(1)Edlcos 180^(@)` `therefore oint vec(E ).vec(d)l=E_(0)h "" [sin (kz_(2)-omega t)-sin(kz_(1)-omega t)] ""`....(1) |
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