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A plane is flying at a constant height and constant speed of 300sqrt2 m//s along (hati+hatj)/(sqrt2) vector. At time t = 0, an observer in a car moving with velocity 30hatjm//s is at -300hatjm and the plane is at 400 km. At this instant a stone is thrown from the plane vertically upwards w.rt. the plane and with a velocity of 10(30hati+27hatj+hatk) m//s relative to the car. (take g = 10 m//s^(2)). The distance(in km) between the stone and the car when the stone hits ground is 4.73K. Find K (Take sqrt2 = 1.41)

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