A plane light wave of wavelength lambda = 700nm falls normally on the base of a biprism made of glass (mu = 1.560) width refracting angle theta = 5^(@). A plate is placed behind the biprism and the space between them is filled with a liquid of refractive index (mu' = 1.500). Find the fringe width on a screen behind the biprism.

A plane light wave of wavelength lambda = 700nm falls normally on the

1.	A plane light wave of wavelength lambda = 700nm falls normally on the base of a biprism made of glass (mu = 1.560) width refracting angle theta = 5^(@). A plate is placed behind the biprism and the space between them is filled with a liquid of refractive index (mu' = 1.500). Find the fringe width on a screen behind the biprism.
Answer» ANSWER :`[66.8 MUM]`

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