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A plane mirror is made of glass having thickness 1.5 cm. its back surface is coated with mercury. A man is standing at a distance of 50 cm from the front face of the mirror. If he looks at the mirror normally, where can he find his image behind the front face of the mirror? Refractive index of glass = 1.5. |
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Answer» Solution :Real DEPTH of the mercury coated surface from the UPPER surface of the mirror = 1.5 CM If the apparent depth of the mercury coated surface is x cm, then `(1.5)/(x) = 1.5 or, x = 1cm` So the mercury coated surface APPEARS to be at a distance of 1 cm from the front face to the mirror. Therefore, the distance of the MAN from the apparent position of the mercury coated surface = 50 + 1 = 51 cm So the distance of the image from the apparent position of the mercury coated surface = 51 cm `therefore` The distance of the image of the man from the front surface of the mirror = 51 + 1 52cm. |
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