1.

A plane monochromic light falls normally on a diaphragm with two narrow slits separated by a distance d = 2.5mm. A fringe pattern is formed on the screen placed at D = 100 cm behind the diaphragm.If one of the slits is covered by a glass plate of thickness 10 mu m, then distance by which these fringes will be shifted is :

Answer»

2 mm
3 mm
4 mm
5 mm

Solution :`(MU -1) t = (xd)/(D)`
`therefore X = ((mu - 1)t D)/(d) = 0.2 cm`


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