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A plane polarized light is incident perpendicularly on polaroid. Taking incident light as an axis polaroid is rotated with an angular speed pi rads^(-1). If light energy incident in 1s is 4 mJ. How much energy will emerge after one rotation ? |
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Answer» Solution :`int_(0)^(T)cos^(2)omegatdt=(pi)/(omega)` Here, `I_(0)=4mJ=4xx10^(-3)J,omega=pi" rad "s^(-1)` `I=I_(0)cos^(2)omegat` `:.` ENERGY emerging during one rotation, `=int_(0)^(T)I_(0)cos^(2)omegatdt` `=(I_(0)pi)/(omega)` `=(4xx10^(-3)xxpi)/(pi)` `4xx10^(-3)J` |
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