A plane sheet has a uniformly distributed charge. Origin is selected at the middle of the sheet (in yz plane). A charge +Q is moved from point A (10a, 2a,0) to point B (10a,0,2a) along a circle and then to point C(10a, 0, 0). If the initial electrostatic potential energy is U_0, what will be final electrostatic potential energy?

A plane sheet has a uniformly distributed charge. Origin is selected a

1.	A plane sheet has a uniformly distributed charge. Origin is selected at the middle of the sheet (in yz plane). A charge +Q is moved from point A (10a, 2a,0) to point B (10a,0,2a) along a circle and then to point C(10a, 0, 0). If the initial electrostatic potential energy is U_0, what will be final electrostatic potential energy?
Answer» zero `U_0` `U_0(sqrt2)` `U_0/2` Solution :b. The ELECTRIC field will be as shown. `A` flat surface of cylinder of radius `2a` and length `10a` will be an EQUIPOTENTIAL surface. Points `A` and `B` are LOCATED on a circle forming flat surface of the cylinder. The electric field is perpendicular at all the points of this plane surface. THUS, there will be no-change in electrostic `PE` in moving the charge `+Q` on this plane surface.

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