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A plane wave front of wavelength `lamda` is incident on a single slite of width b. What is the angular width for secondary maximum ?A. `(lambda)/(2b)`B. `(lambda)/(b)`C. `(2lambda)/(b)`D. `(b)/(lambda)` |
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Answer» Correct Answer - B `beta=(lambdaD)/(d) and theta=(beta)/(D)` `therefore theta=(lambda)/(d)` `therefore` Width of single slit = b So, `theta=(lambda)/(b)` |
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