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A planet has twice the radius but the mean density is `1/4` th as compared to earth. What is the ratio of escape velocity from earth to that from the planetA. `1:1`B. `1:2`C. `2:1`D. `3:1` |
Answer» Correct Answer - A `v_(e )=sqrt((2GM)/(R ))=sqrt((2G4pi R^(3)d)/(3))=2sqrt(2)R sqrt((G pi d)/(3))` `therefore (v_(e))/(v_(p))=(2sqrt(2)R sqrt((G pi d)/(3)))/(2sqrt(2)2R sqrt((G pi)/(3)(d)/(4)))=1` |
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