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A planet has twice the radius but the mean density is `1/4` th as compared to earth. What is the ratio of escape velocity from earth to that from the planetA. `3:1`B. `1:2`C. `1:1`D. `2:1` |
Answer» Correct Answer - c `(v_(rho_(2)))/(v_(rho_(1)))=(R_(2))/(R_(1))sqrt((rho_(2))/(rho_(1)))=2xxsqrt((1)/(4))=2xx(1)/(2)=1` `(v_(rho_(2)))/(v_(rho_(1)))=(1)/(1)` |
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