A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 km s^(-1), the escape velocity from the surface of the planet would be :

A planet in a distant solar system is 10 times more massive than the e

1.	A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 km s^(-1), the escape velocity from the surface of the planet would be :
Answer» `1.1km s^(-1)` `11 KM s^(-1)` `110 km s^(-1)` `0.11km s^(-1)` Solution :`((V_(e ))_(2))/((V_(e ))_(1))=(sqrt((2GM_(2))/(R_(2))))/(sqrt((2GM_(1))/(R_(1))))=sqrt((M_(2))/(M_(1))XX(R_(1))/(R_(2)))=sqrt(10xx10)=10` `therefore (V_(e))_(2)=10xx11=110km//s` So CORRECT choice is (c )`.

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A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11 km s^(-1), the escape velocity from the surface of the planet would be :

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