InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A planet is revolving around a star in a circular orbit of radius R with a period T. If the gravitational force between the planet and the star is proportional to `R^(-3//2)`, thenA. `T^(2)prop R^(5//2)`B. `T^(2)prop R^(-7//2)`C. `T^(2)prop R^(3//2)`D. `T^(2)prop R^(4)` |
|
Answer» Correct Answer - A The C.P. force is provided by the gravitational force. `therefore (mv^(2))/(R )=(GMm)/(R^(3//2))` `therefore mR omega^(2)=(GMm)/(R^(3//2))` `therefore R omega^(2)prop R^(-3//2)` or `omega^(2)=R^(-5//2)` `therefore ((2pi)/(T))^(2)prop R^(-5//2)` `therefore (4pi^(2))/(T^(2))prop (1)/(R^(5//2))` or `T^(2)prop R^(5//2)" "` [Option (a)] |
|