1.

A planet moves around the sun. At a given point P, it is closest from the sun at a distance d_(1) and has a speed v_(1). At another point Q, when it is farther from the sun at a distance d_(2), its speed will be

Answer»

`(d_(1)^(2))/(d_(2)^(2))v_(1)`
`(d_(2))/(d_(1))v_(1)`
`(d_(2)^(2))/(d_(1)^(2))v_(1)`
`(d_(1)v_(1))/(d_(2))`

SOLUTION :ANGULAR momentum is conserved.
`mv_(1)d_(1)=mv_(2)d_(2) rArr v_(2)=(v_(1)d_(1))/(d_(2))`.


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