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A planet revolves about the sun in elliptical orbit. The arial velocity `((dA)/(dt))` of the planet is `4.0xx10^(16) m^(2)//s`. The least distance between planet and the sun is `2xx10^(12) m`. Then the maximum speed of the planet in `km//s` is -A. `10`B. `20`C. `40`D. None of these |
Answer» Correct Answer - c `2m(dA)/(dt)=mvr` `2xx4xx10^(16)=v_(max)xx2xx10^(12)` `v_(max)=40 km//s` |
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