InterviewSolution
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InterviewSolution
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A planet revolves about the sun in elliptical orbit. The arial velocity `((dA)/(dt))` of the planet is `4.0xx10^(16) m^(2)//s`. The least distance between planet and the sun is `2xx10^(12) m`. Then the maximum speed of the planet in `km//s` is -A. 10B. 20C. 40D. None of these |
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Answer» Correct Answer - C `(dA)/(dt) = (r^(2)omega)/(2)` is constant `therefore (dA)/(dt) = (r_(max)^(2)omega_(min))/(2)=(r_(min)^(2)omega_(max))/(2)` `rArr omega_(min) = (2dA//dt)/(r_(max)^(2))` `V_(max)=omega_(min)r_(min)=(2dA//dt)/(r_(min))=40k m//s` |
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