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A plank with a small block on top of it is under going vertical `SHM`. Its period is `2 sec`. The minium amplitude at which the block will separate from plank is :A. `(10)/(pi^2)`B. `(pi^2)/(10)`C. `(20)/(pi^2)`D. `(20)/(pi^2)` |
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Answer» Correct Answer - A Here `g=Aomega^2` `A=(g)/(omega^2)=(g)/(((2pi)/(T))^2)=(gT^2)/(4pi^2)` `=(10xx4)/(4pi^2)=(10)/(pi^2)m` |
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