A plate with plane parallel faces having refractiv index 1.8 rests on a plane mirror. A light ray is incident on the upper face of the plate at 60^@. How far from the entry point will the ray emerge after reflection by the mirror. The plate is 6cm thick?

A plate with plane parallel faces having refractiv index 1.8 rests on

1.	A plate with plane parallel faces having refractiv index 1.8 rests on a plane mirror. A light ray is incident on the upper face of the plate at 60^@. How far from the entry point will the ray emerge after reflection by the mirror. The plate is 6cm thick?
Answer» Solution :`mu=sin i/sin R` `1.8=sin60^@/sinr` Solving, we get `r=28.8^@` `MP=PQ TANR` `:. MN=2(MP)=2PQ.tanr` `=2xx6xxtan 28.8^@` `=6.6 CM` `mu=sin45^@/sinr=4/3`

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A plate with plane parallel faces having refractiv index 1.8 rests on a plane mirror. A light ray is incident on the upper face of the plate at 60^@. How far from the entry point will the ray emerge after reflection by the mirror. The plate is 6cm thick?

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