1.

A plot of k vs 1//T for a reaction gives the slope -1 xx 10^(4) K. The energy of activation for the reaction is:

Answer»

8314 J `mol^(-1)`
`1.202 kJmol^(-1)`
`12.02 J mol^(-1)`
`83.14 kJ mol^(-1)`

Solution :d) Plot of In k vs `1//T` GIVES
Slope = `-E_(a)/R`
`-1xx10^(4) = -(EA)/R`
`Ea=Rxx(1xx10^(4))`
`=8.314 XX 10^(4)Jmol^(-1)=83.14 xx 10^(3)J mol^(-1)`
`=83.14kJ mol^(-1)`


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