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A plot of the number of neutrons (n) against the number of protons (p) of stable nuclei exhibits upward deviation from linearity for atomic number, Z gt 20. For an unstable nucleus having n//p ratio less than 1, the possible mode (s) of decay is (are) |
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Answer» `beta^(-) -` decay (`beta` EMISSION) Positron emission `OVERSET(.^(a)X^(b))rarr + ._(1)^(0)e + ._(a -1)Y^(b)` `rArr K -` electron capture `._(a)X^(b) + ._(-1)e^(0) rarr ._(a -1)Y^(b)` both process cause an increase in n/p ratio towards 1 THUS STABILISING the nucleus |
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