InterviewSolution
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InterviewSolution
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A point charge of 10−9 C is placed at a point A in free space. Calculate : (i) the intensity of electrostatic field on the surface of sphere of radius 5 cm and centre A.(ii) the difference of potential between two points 20 cm and 10 cm away from the charge at A. |
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Answer» (i) E = Q/4πε0 r2 = 10−9/4π × 8.854 × 10−12 × (5 × 10−2)2 = 3,595 V/m (ii) Potential of first point = Q/4πε0d = 10−9/4π × 8.854 × 10−12 × 0.2 = 45V Potential of second point = 10−9 /4π × 8.854 × 10−12 × 0.1 = 90V ∴ p.d. between two points = 90 − 45 = 45 V |
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