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InterviewSolution
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The small identical conducting spheres have charges of 2.0 × 10−9 C and − 0.5 × 10−9 respectively. When they are placed 4 cm apart, what is the force between them ? If they are brought into contact and then separated by 4 cm, what is the force between them ? |
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Answer» F = 9 × 10−9 Q1 Q2/d2 = 9 × 10−9 × (− 0.5 × 10−9 )/0.042 = − 56.25 × 10−7 N. When two identical spheres are brought into contact with each other and then separated, each gets half of the total charge. Hence, Q1 = Q2 = [2 × 10−9 + (− 0.5 × 10−9)/2] = 0.75 × 10−9C When they are separated by 4cm, F = 9 × 10−9 × (0.75 × 10−9)2/0.042 = 0.316 × 10−5N |
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