1.

A point charge q_1 is placed inside cavity 1 and another point charge q_2 is inside cavity 2. A point charge q is placed outside the conductor. For the situation described above, answer the following questions. If q_1 is at the center of cavity 1, then vecE at point S, at a distant r from the center of cavity 1(rgtr_1), due to the induced charge on outer surface of the conductor , would be

Answer»

`q_1//4piepsilon_0r^(2)` AWAY from the CENTER of cavity 1
`q_1//4piepsilon_0r_(1)^(2)` away from the center of cavity 1
zero
`q_1//4piepsilon_0r^2` toward the center of cavity 1

SOLUTION :Electric field intensity outside the cavity to `q_(1)` and `-q_(1)` would be zero
`vec(E)_(q1)+vec(E)_(-q1)=0`
`vecE_(-q1)=-vec(E)_(q1)=(q_(1))/(4piepsilon_(0)r^(2))` toward centre of cavity 1


Discussion

No Comment Found

Related InterviewSolutions