1.

A point charge q_1 is placed inside cavity 1 and another point charge q_2 is inside cavity 2. A point charge q is placed outside the conductor. For the situation described above, answer the following questions. If the potential of the conductor is V_0 and charge q_2 is placed at the center of cavity 2, then potential at point Q is

Answer»

`q_2/(4piepsilon_0r'^2) + V_0`
`(q_2)/(4piepsilon_0)(1/R'_(2) + 1/r_(2)) + V_0`
`(q_2)/(4piepsilon_0)(1/r'_(2) - 1/r_(2)) + V_0`
`V_0`

Solution :Potential at POINT Q `=` potential of CONDUCTOR `+` potential due to `q_(2)+` potential due to `-q_(2)`
`=V_(0)+(q_(2))/(4piepsilon_(0)r_(2))=(q_(2))/(4piepsilon_(0))((1)/(r'_(2))-(1)/(r_(2)))+V_(0)`


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