A point charge .Q. is placed at a point inside the cone as shown. The flux due to the charge through the curved surface is given as (2 Q)/(3 epsilon_(0)). Now another charge .Q. is placed vertically above at the same distance from the base. The flux through the curved surface due to both charges is .

A point charge .Q. is placed at a point inside the cone as shown. The

1.	A point charge .Q. is placed at a point inside the cone as shown. The flux due to the charge through the curved surface is given as (2 Q)/(3 epsilon_(0)). Now another charge .Q. is placed vertically above at the same distance from the base. The flux through the curved surface due to both charges is .
Answer» `(Q)/(3 epsilon_(0))` `(2Q)/(3 epsilon_(0))` `(Q)/(epsilon_(0))` `(2Q)/(epsilon_(0))` ANSWER :C

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