1.

A point charge q is placed at origin. Let E_A, E_B " and " E_c be the electric fields at three points A (1,2,3) , B (1,1,-1) and C (2,2,2) respectively due to the charge q. Then , the relation between them is 1. E_A bot E_B ""2.E_A || E_c 3. |E_B|=4|E_c| "" 4.|E_B|=8|E_c|

Answer»

1,4 are correct
2,4 are correct
1,3 are correct
2,3 are correct

Solution :In VECTOR form, we WRITE expressions of field at A,B and C
`E_(A)= { (KQ)/((1^2 + 2^2+3^2)^(3//2))} ( hat I + 2 hat j + 3 hat k)`
`E_(B)= (kq)/((1^2+1^2+(-1)^2)^(3//2)).(hati+hatj-HATK)`
`E_( C)= (kq)/((2^2+2^2+2^2)^(3//2)).(2 hat i+2 hatj+2 hatk)`
`E_(A)= (kq)/(14^(3//2))(hati+2hatj+3hatk)`
`E_(B)= (kq)/(3^(3//2))(hati+hatj-hatk)`
`E_(C)= (kq)/(12^(3//2))(2hati+hatj+2hatk)`
As, `E_(A)_|_E_(B)=0 and E_B =4 |E_C|`


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