Saved Bookmarks
| 1. |
A point charge Q is placed at point O as shown in the figure. Is the potential difference V_A-V_B positive, negative or zero, if Q is (i) positive (ii) negative ? |
|
Answer» SOLUTION :(i) If CHARGE Q is POSITIVE, then `V_A - V_B = Q/(4pi epsi_0) [ 1/r_A - 1/r_B] = +ve` (ii) If charge Q is negative, then `V_A-V_B` is negative.
|
|