1.

A point charge q is placed at the centre of a cube of side length L . The electric flux emerging from the cube is……

Answer»

`Q/e_0`
zero
`(6ql)^2/e_0`
`q/(6L^2 e_0)`

Solution :Here given closed surface, enclosed charge q . Hence whatever electric flux is emanating from charge q. Same amount is passing through surrounding ENCLOSING surface (here surface of CUBE). This amount is given by Gauss.s LAW.
`phi=q/e_0`


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