A point electric dipole with a moment `p` is placed in the external uniform electric field whose strength equals `E_(0)`. With `p uarr uarr E_(0)`. In this case one of the equipotential surfaces enclosing the dipole from a sphere. Find the radius of this sphere.

A point electric dipole with a moment `p` is placed in the external un

1.	A point electric dipole with a moment `p` is placed in the external uniform electric field whose strength equals `E_(0)`. With `p uarr uarr E_(0)`. In this case one of the equipotential surfaces enclosing the dipole from a sphere. Find the radius of this sphere.
Answer» Correct Answer - `r = sqrt((p)/(4 pi epsi_(0)E_(0)))`

Two identical dipoles have their axes at right angles to each other and also bisecting each other . Calculate the field at a distance r from the point of intersection of their axes in a direction `theta` with the axis of one of the dipoles . The dipole moment of each dipole is equal to p .
ABC is a very small equilateral triangles of side `0.5 xx 10^(-3)` m . A charge of `+20` aC (attocoulomb) is placed at the corner A and two charges , each of `-10`aC , at B and C . Calculate the potential at a point on the prolongation of AC 2 cm away from A . [Hint: 1 aC (attocoulomb = `10^(-18)` coulomb]
A dipole of electric moment p is located at a distance r from a long thread charged with a linear density `lambda` . Find the force on the dipole if (a) if is placed parallel to the thread , (b) perpendicular to the thread . [Hint : Field due to long thread = `(1)/(2 pi epsi_(0)) (lambda)/(r)`]
A point electric dipole with a moment `p` is placed in the external uniform electric field whose strength equals `E_(0)`. With `p uarr uarr E_(0)`. In this case one of the equipotential surfaces enclosing the dipole from a sphere. Find the radius of this sphere.
Calculate the energy released in the formation of 1 kg hydrogen chloride , given that the dipole moment of hydrogen chloride molecules is `3.44 xx 10^(-30)` C m and the separation between hydrogen and chlorine atoms in the equilibrium position is `1.01 xx 10^(-10)` m .