1.

A point mass initially at rest moves along x-axis. Its acceleration varies with time as a = 6t+ 5 ms. If it starts from origin, the distance covered by it in 1 s is

Answer»

3 m
5.5 m
3.5 m
4 m

Solution :Here ACCELERATION =6t+5
`(dv)/(dt)=6t+5`
or dv=(6t+5) dt, Intergrating
`v=(6t^(2))/(2)+5t=3T^(2)+5t`
`DS(3t^(2)+5t)dt`
`s=(3t^(3))/(3)+(5t^(2))/(2)`
`(s)_(t)=(3xx1xx1)/(3)+(5)/(2)1xx1=3.5`


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