InterviewSolution
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InterviewSolution
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A point mass oscillates along the `x-`acis according to the law `x = x_(0)cos(omegat - pi//4)` if the acceleration of the particle is written as, a `= A cos(omega + delta)`, then :A. `A = x_(0), delta = -pi//4`B. `A = x_(0)omega^(2), delta = -pi//4`C. `A = x_(0)omega^(2), delta = -pi//4`D. `A = x_(0)omega^(2), delta = 3pi//4` |
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Answer» Correct Answer - D `x = x_(0)cos(omegat - (pi)/(4)), v = -x_(0)omegasin(omegat - (pi)/(4))` `a = -x_(0)omega^(2)cos(omegat - (pi)/(4)), a = x_(0)omega^(2)cos(omegat - (pi)/(4) + pi)` `a = x_(0)omega^(2)cos(omegat + (3m)/(4))` |
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