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A point moves along a circle having a radius `20cm` with a constant tangential acceleration `5cm//s^(2)` . How much time is needed after motion begins for the normal acceleration of the point to be equal to tangential acceleration?A. `1s`B. `2s`C. `3s`D. `4s` |
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Answer» Correct Answer - B `(v^(2))/(R)=a_(t)=a` (Here, `a_(t)=`asay) or `((at)^(2))/(R)=a` :. `t=sqrt((R)/(a))=sqrt((20)/(5))=2s` |
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