A point object is kept at a distance of 2m from origin on x- axis. A quarter cylinder of radius R=30 cm and refractive index mu=1.5 having its axis _|__(r) to plane of paper is placed between the object and the parabolic reflector at a distance of 130cm from origin as shown in figure. The position of the image after reflection from the parabolic reflector y^(2)=2x is 25lamdacm. Find the value of lamda?

A point object is kept at a distance of 2m from origin on x- axis. A q

1.	A point object is kept at a distance of 2m from origin on x- axis. A quarter cylinder of radius R=30 cm and refractive index mu=1.5 having its axis _\|__(r) to plane of paper is placed between the object and the parabolic reflector at a distance of 130cm from origin as shown in figure. The position of the image after reflection from the parabolic reflector y^(2)=2x is 25lamdacm. Find the value of lamda?
Answer» Solution :After refraction through the quarter cylinder the emergent rays falls on the parabolic reflector PARALLEL to `x` -AXIS `tan(pi-theta)=-1/((DY)/(dx)\|_((x_(1),y_(1))))=y_(1)` `tan2theta=(2tantheta)/(1-tan^(2)theta)=(y_(1))/(x_(2)-x_(1))` `impliesx_(2)=1/2m=50cm`

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