A point object moves on a circular path such that distance covered by it is given by function S=(t^(2)/(2)+2t) meter ( t in second). The ratio of the magnitude of acceleration at t = 2 s and t = 5 s. is 1: 2 then the radius of the circle is

A point object moves on a circular path such that distance covered by

1.	A point object moves on a circular path such that distance covered by it is given by function S=(t^(2)/(2)+2t) meter ( t in second). The ratio of the magnitude of acceleration at t = 2 s and t = 5 s. is 1: 2 then the radius of the circle is
Answer» 1 m `3sqrt(51) m` `SQRT(51) m` 3 m Answer :B

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A point object moves on a circular path such that distance covered by it is given by function S=(t^(2)/(2)+2t) meter ( t in second). The ratio of the magnitude of acceleration at t = 2 s and t = 5 s. is 1: 2 then the radius of the circle is

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